5y^2-52y+160=0

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Solution for 5y^2-52y+160=0 equation: 



5y^2-52y+160=0

a = 5; b = -52; c = +160;
Δ = b2-4ac
Δ = -522-4·5·160
Δ = -496
Delta is less than zero, so there is no solution for the equation

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